CppCon 2017: Herb Sutter “Meta: Thoughts on generative C++”

The talk about the reflection proposal was amazing. Meta classes are also very cool. We can only hope it comes fast. ▶ this video

in “Outperforming LAPACK with C++ metaprogramming” · View on HN

Herb Sutter's talk about it is by far the best talk I've seen from from CppCon17. "Meta: Thoughts on generative C++" - ▶ this video

in “C++17 Is Here: Interview with Herb Sutter” · View on HN

A few years ago Herb Sutter proposed Python-like metaclasses in C++ through compile-time code generation. Not sure if anything has been proposed for general use. ▶ this video

in “Is the preprocessor still needed in C++? (2017)” · View on HN

To a degree, but templates and constexpr don't support a bunch of features like compile-time field enumeration and introspection + code generation. For example, let's say I have a bunch of structs: struct GeoCoordinate { int lat, long; }; struct GeoArea { std::vector<GeoCoordinate> perimeter; }; struct Place { std::string name; std::string contact_number; GeoArea area; }; Now I need to serialize these structs into a format to be sent over the wire. Currently, I have a few choices: 1. Use an off-the-shelf library like protobuf (disclaimer: I work for Google). Then I have to convert my code to a protobuf definition and rely on its code generator to perform [de]serialization. I also have to hope that my library supports all the field definitions I need. 2. Write macros to define each field in each structure. These macros perform some arcane magicks that somehow create the necessary [de]serialization functions. These macros are difficult to write and maintain (or I find a library). 3. Manually define the methods myself. This is tedious, hard to maintain, and error prone. What if I could write some code in C++ which could read the structure and generate the appropriate serialization code? Something like (syntax hypothetical): Serializable(Class) { std::string serialize() { std::string output; for (auto member : Class.members()) { // loop unrolled at compile time if (member.type == int) { output.append(std::format("{:10}"), member.get()) } else if (member.type == std::string) { ...

in “Is the preprocessor still needed in C++? (2017)” · View on HN